How to resolve the algorithm Variadic function step by step in the AutoHotkey programming language

Published on 12 May 2024 09:40 PM
#Autohotkey

How to resolve the algorithm Variadic function step by step in the AutoHotkey programming language

Table of Contents

Problem Statement

Create a function which takes in a variable number of arguments and prints each one on its own line. Also show, if possible in your language, how to call the function on a list of arguments constructed at runtime.

Functions of this type are also known as Variadic Functions.

Let's start with the solution:

Step by Step solution about How to resolve the algorithm Variadic function step by step in the AutoHotkey programming language

Source code in the autohotkey programming language

printAll(args*) {
  for k,v in args
    t .= v "`n"
  MsgBox, %t%
}


printAll(4, 3, 5, 6, 4, 3)
printAll(4, 3, 5)
printAll("Rosetta", "Code", "Is", "Awesome!")


args := ["Rosetta", "Code", "Is", "Awesome!"]
printAll(args*)


string = Mary had a little lamb
StringSplit, arg, string, %A_Space%

Function(arg1,arg2,arg3,arg4,arg5)  ;Calls the function with 5 arguments.
Function()  ;Calls the function with no arguments.
return

Function(arg1="",arg2="",arg3="",arg4="",arg5="") {
  Loop,5
    If arg%A_Index% !=
      out .= arg%A_Index% "`n"
  MsgBox,% out ? out:"No non-blank arguments were passed."
}

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