How to resolve the algorithm Visualize a tree step by step in the Perl programming language

Published on 12 May 2024 09:40 PM

How to resolve the algorithm Visualize a tree step by step in the Perl programming language

Table of Contents

Problem Statement

A tree structure   (i.e. a rooted, connected acyclic graph)   is often used in programming.
It's often helpful to visually examine such a structure. There are many ways to represent trees to a reader, such as: Write a program to produce a visual representation of some tree.
The content of the tree doesn't matter, nor does the output format, the only requirement being that the output is human friendly. Make do with the vague term "friendly" the best you can.

Let's start with the solution:

Step by Step solution about How to resolve the algorithm Visualize a tree step by step in the Perl programming language

Source code in the perl programming language

#!/usr/bin/perl
use warnings;
use strict;
use utf8;
use open OUT => ':utf8', ':std';

sub parse {
    my ($tree) = shift;
    if (my ($root, $children) = $tree =~ /^(.+?)\((.*)\)$/) {

        my $depth = 0;
        for my $pos (0 .. length($children) - 1) {
            my $char = \substr $children, $pos, 1;
            if (0 == $depth and ',' eq $$char) {
                $$char = "\x0";
            } elsif ('(' eq $$char) {
                $depth++;
            } elsif (')' eq $$char) {
                $depth--;
            }
        }
        return($root, [map parse($_), split /\x0/, $children]);

    } else { # Leaf.
        return $tree;
    }
}

sub output {
    my ($parsed, $prefix) = @_;
    my $is_root = not defined $prefix;
    $prefix //= ' ';
    while (my $member = shift @$parsed) {
        my $last = !@$parsed || (1 == @$parsed and ref $parsed->[0]);
        unless ($is_root) {
            substr $prefix, -3, 1, ' ';
            substr($prefix, -4, 1) =~ s/├/│/;
            substr $prefix, -2, 1, ref $member ? ' ' : '└' if $last;
        }

        if (ref $member) {
            output($member, $prefix . '├─');
        } else {
            print $prefix, $member, "\n";
        }
    }
}

my $tree = 'a(b0(c1,c2(d(ef,gh)),c3(i1,i2,i3(jj),i4(kk,m))),b1(C1,C2(D1(E),D2,D3),C3))';
my $parsed = [parse($tree)];
output($parsed);


  

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