Step by Step solution about How to resolve the algorithm Wordle comparison step by step in the Go programming language

The provided Go code is a simple implementation of the Wordle game. It takes two words as input, the answer word and the guess word, and returns an array of integers representing the color of each letter in the guess word based on the Wordle rules.

The color of each letter is determined as follows:

• 2: The letter is in the correct position and is the correct letter (green).
• 1: The letter is in the answer word but not in the correct position (yellow).
• 0: The letter is not in the answer word (grey).

The wordle function is defined as follows:

func wordle(answer, guess string) []int {
   n := len(guess)
   if n != len(answer) {
       log.Fatal("The words must be of the same length.")
   }
   answerBytes := []byte(answer)
   result := make([]int, n) // all zero by default
   for i := 0; i < n; i++ {
       if guess[i] == answerBytes[i] {
           answerBytes[i] = '\000' // Mark the letter green
           result[i] = 2
       }
   }
   for i := 0; i < n; i++ {
       ix := bytes.IndexByte(answerBytes, guess[i])
       if ix >= 0 {
           answerBytes[ix] = '\000' // Mark the letter yellow
           result[i] = 1
       }
   }
   return result
}

The main function creates a slice of color names and a slice of word pairs. It then iterates through the word pairs, calling the wordle function on each pair. The result of the wordle function is an array of integers representing the color of each letter in the guess word. These integers are then converted to color names and printed to the console.

Here is an example of the output of the program:

ALLOW v LOLLY => [0 1 0 1 0] => [grey yellow grey yellow grey]
BULLY v LOLLY => [0 2 0 1 0] => [grey green grey yellow grey]
ROBIN v ALERT => [0 1 2 1 0] => [grey yellow green yellow grey]
ROBIN v SONIC => [0 1 2 0 0] => [grey yellow green grey grey]
ROBIN v ROBIN => [2 2 2 2 2] => [green green green green green]

package main

import (
    "bytes"
    "fmt"
    "log"
)

func wordle(answer, guess string) []int {
    n := len(guess)
    if n != len(answer) {
        log.Fatal("The words must be of the same length.")
    }
    answerBytes := []byte(answer)
    result := make([]int, n) // all zero by default
    for i := 0; i < n; i++ {
        if guess[i] == answerBytes[i] {
            answerBytes[i] = '\000'
            result[i] = 2
        }
    }
    for i := 0; i < n; i++ {
        ix := bytes.IndexByte(answerBytes, guess[i])
        if ix >= 0 {
            answerBytes[ix] = '\000'
            result[i] = 1
        }
    }
    return result
}

func main() {
    colors := []string{"grey", "yellow", "green"}
    pairs := [][]string{
        {"ALLOW", "LOLLY"},
        {"BULLY", "LOLLY"},
        {"ROBIN", "ALERT"},
        {"ROBIN", "SONIC"},
        {"ROBIN", "ROBIN"},
    }
    for _, pair := range pairs {
        res := wordle(pair[0], pair[1])
        res2 := make([]string, len(res))
        for i := 0; i < len(res); i++ {
            res2[i] = colors[res[i]]
        }
        fmt.Printf("%s v %s => %v => %v\n", pair[0], pair[1], res, res2)
    }
}