How to resolve the algorithm Y combinator step by step in the Rust programming language

Published on 12 May 2024 09:40 PM

How to resolve the algorithm Y combinator step by step in the Rust programming language

Table of Contents

Problem Statement

In strict functional programming and the lambda calculus, functions (lambda expressions) don't have state and are only allowed to refer to arguments of enclosing functions. This rules out the usual definition of a recursive function wherein a function is associated with the state of a variable and this variable's state is used in the body of the function. The   Y combinator   is itself a stateless function that, when applied to another stateless function, returns a recursive version of the function. The Y combinator is the simplest of the class of such functions, called fixed-point combinators.

Define the stateless   Y combinator   and use it to compute factorials and Fibonacci numbers from other stateless functions or lambda expressions.

Let's start with the solution:

Step by Step solution about How to resolve the algorithm Y combinator step by step in the Rust programming language

Source code in the rust programming language

//! A simple implementation of the Y Combinator:
//! λf.(λx.xx)(λx.f(xx))
//! <=> λf.(λx.f(xx))(λx.f(xx))

/// A function type that takes its own type as an input is an infinite recursive type.
/// We introduce the "Apply" trait, which will allow us to have an input with the same type as self, and break the recursion.
/// The input is going to be a trait object that implements the desired function in the interface.
trait Apply<T, R> {
    fn apply(&self, f: &dyn Apply<T, R>, t: T) -> R;
}

/// If we were to pass in self as f, we get:
/// λf.λt.sft
/// => λs.λt.sst [s/f]
/// => λs.ss
impl<T, R, F> Apply<T, R> for F where F: Fn(&dyn Apply<T, R>, T) -> R {
    fn apply(&self, f: &dyn Apply<T, R>, t: T) -> R {
        self(f, t)
    }
}

/// (λt(λx.(λy.xxy))(λx.(λy.f(λz.xxz)y)))t
/// => (λx.xx)(λx.f(xx))
/// => Yf
fn y<T, R>(f: impl Fn(&dyn Fn(T) -> R, T) -> R) -> impl Fn(T) -> R {
    move |t| (&|x: &dyn Apply<T, R>, y| x.apply(x, y))
             (&|x: &dyn Apply<T, R>, y| f(&|z| x.apply(x, z), y), t)
}

/// Factorial of n.
fn fac(n: usize) -> usize {
    let almost_fac = |f: &dyn Fn(usize) -> usize, x| if x == 0 { 1 } else { x * f(x - 1) };
    y(almost_fac)(n)
}

/// nth Fibonacci number.
fn fib(n: usize) -> usize {
    let almost_fib = |f: &dyn Fn((usize, usize, usize)) -> usize, (a0, a1, x)|
        match x {
            0 => a0,
            1 => a1,
            _ => f((a1, a0 + a1, x - 1)),
        };

    y(almost_fib)((1, 1, n))
}

/// Driver function.
fn main() {
    let n = 10;
    println!("fac({}) = {}", n, fac(n));
    println!("fib({}) = {}", n, fib(n));
}

  

You may also check:How to resolve the algorithm Shell one-liner step by step in the Sidef programming language
You may also check:How to resolve the algorithm Death Star step by step in the Yabasic programming language
You may also check:How to resolve the algorithm Terminal control/Positional read step by step in the XPL0 programming language
You may also check:How to resolve the algorithm Anti-primes step by step in the Groovy programming language
You may also check:How to resolve the algorithm Hello world/Text step by step in the PicoLisp programming language