How to resolve the algorithm Zero to the zero power step by step in the Julia programming language
How to resolve the algorithm Zero to the zero power step by step in the Julia programming language
Table of Contents
Problem Statement
Some computer programming languages are not exactly consistent (with other computer programming languages) when raising zero to the zeroth power: 00
Show the results of raising zero to the zeroth power.
If your computer language objects to 0**0 or 0^0 at compile time, you may also try something like:
Show the result here. And of course use any symbols or notation that is supported in your computer programming language for exponentiation.
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Zero to the zero power step by step in the Julia programming language
The provided Julia source code is a simple script that demonstrates the exponentiation operation (^
) for different numeric types in Julia. It uses the using Printf
statement to enable formatted printing.
The const types
line defines a tuple containing the following numeric types: Complex
, Float64
, Rational
, Int
, and Bool
.
The for
loop iterates over all pairs of types in the types
tuple, using the Tb
and Te
variables to represent the base and exponent types, respectively.
Inside the loop, the zb
and ze
variables are initialized to zero values of the Tb
and Te
types, respectively. The r
variable is then set to the result of raising zb
to the power of ze
.
The @printf
statement is used to print information about the types and values involved in the exponentiation operation. It uses formatted strings to specify the alignment and width of the printed values.
The output of the program will be a table showing the results of raising zb
to the power of ze
for all combinations of types in the types
tuple. Each row in the table will show the base type (Tb
), exponent type (Te
), base value (zb
), exponent value (ze
), result value (r
), and the type of the result (typeof(r)
).
For example, if the types
tuple contains Complex
, Float64
, Rational
, Int
, and Bool
, the output might look something like this:
Complex ^ Complex = 0.000000+0.000000i ^ 0.000000+0.000000i = 0.000000+0.000000i (Complex{Float64})
Complex ^ Float64 = 0.000000+0.000000i ^ 1.000000 = 0.000000+0.000000i (Complex{Float64})
Complex ^ Rational = 0.000000+0.000000i ^ 1/1 = 0.000000+0.000000i (Complex{Float64})
Complex ^ Int = 0.000000+0.000000i ^ 1 = 0.000000+0.000000i (Complex{Float64})
Complex ^ Bool = 0.000000+0.000000i ^ 0 = 1.000000+0.000000i (Complex{Float64})
Float64 ^ Complex = 1.000000 ^ 0.000000+0.000000i = 1.000000 (Float64)
Float64 ^ Float64 = 1.000000 ^ 1.000000 = 1.000000 (Float64)
Float64 ^ Rational = 1.000000 ^ 1/1 = 1.000000 (Float64)
Float64 ^ Int = 1.000000 ^ 1 = 1.000000 (Float64)
Float64 ^ Bool = 1.000000 ^ 0 = 1.000000 (Float64)
Rational ^ Complex = 1/1 ^ 0.000000+0.000000i = 1/1 (Rational{BigInt})
Rational ^ Float64 = 1/1 ^ 1.000000 = 1/1 (Rational{BigInt})
Rational ^ Rational = 1/1 ^ 1/1 = 1/1 (Rational{BigInt})
Rational ^ Int = 1/1 ^ 1 = 1/1 (Rational{BigInt})
Rational ^ Bool = 1/1 ^ 0 = 1 (Rational{BigInt})
Int ^ Complex = 1 ^ 0.000000+0.000000i = NaN+NaNim (Complex{Float64})
Int ^ Float64 = 1 ^ 1.000000 = 1.000000 (Float64)
Int ^ Rational = 1 ^ 1/1 = 1 (Int64)
Int ^ Int = 1 ^ 1 = 1 (Int64)
Int ^ Bool = 1 ^ 0 = 1 (Int64)
Bool ^ Complex = 0 ^ 0.000000+0.000000i = NaN+NaNim (Complex{Float64})
Bool ^ Float64 = 0 ^ 1.000000 = 1.000000 (Float64)
Bool ^ Rational = 0 ^ 1/1 = 0 (Rational{BigInt})
Bool ^ Int = 0 ^ 1 = 0 (Bool)
Bool ^ Bool = 0 ^ 0 = 1 (Bool)
Source code in the julia programming language
using Printf
const types = (Complex, Float64, Rational, Int, Bool)
for Tb in types, Te in types
zb, ze = zero(Tb), zero(Te)
r = zb ^ ze
@printf("%10s ^ %-10s = %7s ^ %-7s = %-12s (%s)\n", Tb, Te, zb, ze, r, typeof(r))
end
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