How to resolve the algorithm Zero to the zero power step by step in the Julia programming language

Published on 22 June 2024 08:30 PM

How to resolve the algorithm Zero to the zero power step by step in the Julia programming language

Table of Contents

Problem Statement

Some computer programming languages are not exactly consistent   (with other computer programming languages)   when   raising zero to the zeroth power:     00

Show the results of raising   zero   to the   zeroth   power.

If your computer language objects to     0**0     or     0^0     at compile time,   you may also try something like:

Show the result here. And of course use any symbols or notation that is supported in your computer programming language for exponentiation.

Let's start with the solution:

Step by Step solution about How to resolve the algorithm Zero to the zero power step by step in the Julia programming language

The provided Julia source code is a simple script that demonstrates the exponentiation operation (^) for different numeric types in Julia. It uses the using Printf statement to enable formatted printing.

The const types line defines a tuple containing the following numeric types: Complex, Float64, Rational, Int, and Bool.

The for loop iterates over all pairs of types in the types tuple, using the Tb and Te variables to represent the base and exponent types, respectively.

Inside the loop, the zb and ze variables are initialized to zero values of the Tb and Te types, respectively. The r variable is then set to the result of raising zb to the power of ze.

The @printf statement is used to print information about the types and values involved in the exponentiation operation. It uses formatted strings to specify the alignment and width of the printed values.

The output of the program will be a table showing the results of raising zb to the power of ze for all combinations of types in the types tuple. Each row in the table will show the base type (Tb), exponent type (Te), base value (zb), exponent value (ze), result value (r), and the type of the result (typeof(r)).

For example, if the types tuple contains Complex, Float64, Rational, Int, and Bool, the output might look something like this:

     Complex ^        Complex =  0.000000+0.000000i ^  0.000000+0.000000i =   0.000000+0.000000i (Complex{Float64})
        Complex ^        Float64 =  0.000000+0.000000i ^         1.000000 =   0.000000+0.000000i (Complex{Float64})
        Complex ^        Rational =  0.000000+0.000000i ^         1/1 =   0.000000+0.000000i (Complex{Float64})
        Complex ^           Int =  0.000000+0.000000i ^           1 =   0.000000+0.000000i (Complex{Float64})
        Complex ^          Bool =  0.000000+0.000000i ^           0 =   1.000000+0.000000i (Complex{Float64})
       Float64 ^        Complex =         1.000000 ^  0.000000+0.000000i =         1.000000 (Float64)
       Float64 ^        Float64 =         1.000000 ^         1.000000 =         1.000000 (Float64)
       Float64 ^        Rational =         1.000000 ^         1/1 =         1.000000 (Float64)
       Float64 ^           Int =         1.000000 ^           1 =         1.000000 (Float64)
       Float64 ^          Bool =         1.000000 ^           0 =         1.000000 (Float64)
       Rational ^        Complex =         1/1 ^  0.000000+0.000000i =         1/1 (Rational{BigInt})
       Rational ^        Float64 =         1/1 ^         1.000000 =         1/1 (Rational{BigInt})
       Rational ^        Rational =         1/1 ^         1/1 =         1/1 (Rational{BigInt})
       Rational ^           Int =         1/1 ^           1 =         1/1 (Rational{BigInt})
       Rational ^          Bool =         1/1 ^           0 =         1 (Rational{BigInt})
          Int ^        Complex =           1 ^  0.000000+0.000000i =   NaN+NaNim (Complex{Float64})
          Int ^        Float64 =           1 ^         1.000000 =         1.000000 (Float64)
          Int ^        Rational =           1 ^         1/1 =         1 (Int64)
          Int ^           Int =           1 ^           1 =           1 (Int64)
          Int ^          Bool =           1 ^           0 =           1 (Int64)
         Bool ^        Complex =           0 ^  0.000000+0.000000i =   NaN+NaNim (Complex{Float64})
         Bool ^        Float64 =           0 ^         1.000000 =         1.000000 (Float64)
         Bool ^        Rational =           0 ^         1/1 =         0 (Rational{BigInt})
         Bool ^           Int =           0 ^           1 =           0 (Bool)
         Bool ^          Bool =           0 ^           0 =           1 (Bool)

Source code in the julia programming language

using Printf

const types = (Complex, Float64, Rational, Int, Bool)

for Tb in types, Te in types
    zb, ze = zero(Tb), zero(Te)
    r = zb ^ ze
    @printf("%10s ^ %-10s = %7s ^ %-7s = %-12s (%s)\n", Tb, Te, zb, ze, r, typeof(r))
end


  

You may also check:How to resolve the algorithm Perfect shuffle step by step in the Common Lisp programming language
You may also check:How to resolve the algorithm Monads/List monad step by step in the Python programming language
You may also check:How to resolve the algorithm Sort an array of composite structures step by step in the ooRexx programming language
You may also check:How to resolve the algorithm Array length step by step in the Icon and Unicon programming language
You may also check:How to resolve the algorithm A+B step by step in the TI-89 BASIC programming language