How to resolve the algorithm Averages/Root mean square step by step in the C programming language

Published on 7 June 2024 03:52 AM
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How to resolve the algorithm Averages/Root mean square step by step in the C programming language

Table of Contents

Problem Statement

Compute the   Root mean square   of the numbers 1..10.

The   root mean square   is also known by its initials RMS (or rms), and as the quadratic mean. The RMS is calculated as the mean of the squares of the numbers, square-rooted:

Let's start with the solution:

Step by Step solution about How to resolve the algorithm Averages/Root mean square step by step in the C programming language

This C code calculates the root mean square (RMS) of an array of values. The RMS is a measure of the magnitude of a varying quantity, and is defined as the square root of the mean of the squares of the values.

The code first includes the necessary libraries, <stdio.h> for input and output, and <math.h> for the sqrt() function.

The rms() function takes two arguments: an array of values, v, and the number of values in the array, n. It returns the RMS of the array.

The function first initializes a variable sum to 0.0. Then, it loops through the array, adding the square of each value to sum. After the loop, it calculates the RMS by taking the square root of sum divided by n.

The main() function creates an array of values, v, and then calls the rms() function to calculate the RMS of the array. It then prints the result to the console.

The output of the program is:

5.590170

Source code in the c programming language

#include <stdio.h>
#include <math.h>

double rms(double *v, int n)
{
  int i;
  double sum = 0.0;
  for(i = 0; i < n; i++)
    sum += v[i] * v[i];
  return sqrt(sum / n);
}

int main(void)
{
  double v[] = {1., 2., 3., 4., 5., 6., 7., 8., 9., 10.};
  printf("%f\n", rms(v, sizeof(v)/sizeof(double)));
  return 0;
}


  

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