How to resolve the algorithm Count in octal step by step in the Joy programming language

Published on 12 May 2024 09:40 PM

How to resolve the algorithm Count in octal step by step in the Joy programming language

Table of Contents

Problem Statement

Produce a sequential count in octal,   starting at zero,   and using an increment of a one for each consecutive number. Each number should appear on a single line,   and the program should count until terminated,   or until the maximum value of the numeric type in use is reached.

Let's start with the solution:

Step by Step solution about How to resolve the algorithm Count in octal step by step in the Joy programming language

Source code in the joy programming language

DEFINE
  digit == "01234567" of;
  oct == "\n" [pop 7 >] [[8 div digit] dip cons] while swap digit swons.

0 [0 >=] [dup oct putchars succ] while pop.

  

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