How to resolve the algorithm Count in octal step by step in the Prolog programming language

Published on 12 May 2024 09:40 PM

How to resolve the algorithm Count in octal step by step in the Prolog programming language

Table of Contents

Problem Statement

Produce a sequential count in octal,   starting at zero,   and using an increment of a one for each consecutive number. Each number should appear on a single line,   and the program should count until terminated,   or until the maximum value of the numeric type in use is reached.

Let's start with the solution:

Step by Step solution about How to resolve the algorithm Count in octal step by step in the Prolog programming language

Source code in the prolog programming language

o(O) :- member(O, [0,1,2,3,4,5,6,7]).

octal([O]) :- o(O).
octal([A|B]) :- 
	octal(O), 
	o(T), 
	append(O, [T], [A|B]),
	dif(A, 0).
	
octalize :-
	forall(
		octal(X),
		(maplist(write, X), nl)
	).


  

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