How to resolve the algorithm Euler's sum of powers conjecture step by step in the AWK programming language
Published on 12 May 2024 09:40 PM
How to resolve the algorithm Euler's sum of powers conjecture step by step in the AWK programming language
Table of Contents
Problem Statement
There is a conjecture in mathematics that held for over two hundred years before it was disproved by the finding of a counterexample in 1966 by Lander and Parkin. This conjecture is called Euler's sum of powers conjecture and can be stated as such: In 1966, Leon J. Lander and Thomas R. Parkin used a brute-force search on a CDC 6600 computer restricting numbers to those less than 250. The task consists in writing a program to search for an integer solution of
x
0
5
x
1
5
x
2
5
x
3
5
=
y
5
{\displaystyle x_{0}^{5}+x_{1}^{5}+x_{2}^{5}+x_{3}^{5}=y^{5}}
where all
x
i
{\displaystyle x_{i}}
and
y
{\displaystyle y}
are distinct integers between 0 and 250 (exclusive). Show an answer here. Related tasks are:
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Euler's sum of powers conjecture step by step in the AWK programming language
Source code in the awk programming language
# syntax: GAWK -f EULERS_SUM_OF_POWERS_CONJECTURE.AWK
BEGIN {
start_int = systime()
main()
printf("%d seconds\n",systime()-start_int)
exit(0)
}
function main( sum,s1,x0,x1,x2,x3) {
for (x0=1; x0<=250; x0++) {
for (x1=1; x1<=x0; x1++) {
for (x2=1; x2<=x1; x2++) {
for (x3=1; x3<=x2; x3++) {
sum = (x0^5) + (x1^5) + (x2^5) + (x3^5)
s1 = int(sum ^ 0.2)
if (sum == s1^5) {
printf("%d^5 + %d^5 + %d^5 + %d^5 = %d^5\n",x0,x1,x2,x3,s1)
return
}
}
}
}
}
}
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