Step by Step solution about How to resolve the algorithm Exponentiation order step by step in the Go programming language

The provided Go program demonstrates the use of the math package to perform exponentiation operations. Here's a detailed explanation of the code:

1. package main: This line specifies that the code is part of the main program. In Go, each source file represents a package, and the main package contains the entry point of the program.

2. import "fmt" and import "math": These lines import the fmt and math packages, which are used for formatting output and performing mathematical operations, respectively.

3. Variable Declarations:

   • var a, b, c float64: Declares three floating-point variables named a, b, and c to store the results of the exponentiation operations.

4. Exponentiation Operations:

   • a = math.Pow(5, math.Pow(3, 2)): Calculates 5 raised to the power of 3^2, which is 5^9, and stores the result in the variable a.
   • b = math.Pow(math.Pow(5, 3), 2): Calculates (5^3) raised to the power of 2, which is 5^6, and stores the result in the variable b.
   • c = math.Pow(5, math.Pow(3, 2)): Calculates 5 raised to the power of 3^2, which is the same as the operation performed to calculate a.

5. Output:

   • fmt.Printf("5^3^2 = %.0f\n", a): Prints the value of a in a formatted string, specifying that it should be displayed as a whole number (.0f) and labeled as "5^3^2".
   • fmt.Printf("(5^3)^2 = %.0f\n", b): Similarly, prints the value of b with the label "(5^3)^2".
   • fmt.Printf("5^(3^2) = %.0f\n", c): Prints the value of c with the label "5^(3^2)".

When you run this program, it will calculate and display the results of the three exponentiation operations:

5^3^2   = 1953125
(5^3)^2 = 15625
5^(3^2) = 1953125

As you can see, the results for a and c are identical because they both calculate the same expression: 5 raised to the power of 3^2.

package main

import "fmt"
import "math"

func main() {
    var a, b, c float64
    a = math.Pow(5, math.Pow(3, 2))
    b = math.Pow(math.Pow(5, 3), 2)
    c = math.Pow(5, math.Pow(3, 2))
    fmt.Printf("5^3^2   = %.0f\n", a)
    fmt.Printf("(5^3)^2 = %.0f\n", b)
    fmt.Printf("5^(3^2) = %.0f\n", c)
}