How to resolve the algorithm Multisplit step by step in the Go programming language
How to resolve the algorithm Multisplit step by step in the Go programming language
Table of Contents
Problem Statement
It is often necessary to split a string into pieces based on several different (potentially multi-character) separator strings, while still retaining the information about which separators were present in the input. This is particularly useful when doing small parsing tasks. The task is to write code to demonstrate this. The function (or procedure or method, as appropriate) should take an input string and an ordered collection of separators. The order of the separators is significant: The delimiter order represents priority in matching, with the first defined delimiter having the highest priority. In cases where there would be an ambiguity as to which separator to use at a particular point (e.g., because one separator is a prefix of another) the separator with the highest priority should be used. Delimiters can be reused and the output from the function should be an ordered sequence of substrings. Test your code using the input string “a!===b=!=c” and the separators “==”, “!=” and “=”. For these inputs the string should be parsed as "a" (!=) "" (==) "b" (=) "" (!=) "c", where matched delimiters are shown in parentheses, and separated strings are quoted, so our resulting output is "a", empty string, "b", empty string, "c". Note that the quotation marks are shown for clarity and do not form part of the output. Extra Credit: provide information that indicates which separator was matched at each separation point and where in the input string that separator was matched.
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Multisplit step by step in the Go programming language
This Go program demonstrates how to split a string using multiple separators. Here's a detailed explanation:
-
Package Declaration: The program starts with the
package main
declaration, indicating that this is the main program package. -
Import Statements: It imports the following standard libraries:
"fmt"
: For input and output operations."strings"
: For string manipulation functions.
-
ms
Function:- Arguments: The
ms
function takes two arguments:txt
: The input string to be split.sep
: A slice of separator strings to use for splitting.
- Functionality: It splits the input string
txt
into a slice of strings ([]string
) based on any of the separators in thesep
slice. The function works as follows:- It iterates over the input string
txt
until it becomes empty. - Inside the loop, it finds the first matching separator from the
sep
slice in the remainingtxt
string. It keeps track of the matching separator (sepMatch
) and the position of its first occurrence (posMatch
). - It appends the text before the matching separator to the resulting slice (
ans
). - It updates
txt
by removing the portion that has been added to the result, including the matching separator.
- It iterates over the input string
- Return Value: The
ms
function returns the slice of strings ([]string
) containing the split parts of the input string.
- Arguments: The
-
main
Function:- Functionality: This is the entry point of the program. It calls the
ms
function to demonstrate how to split a string using multiple separators:- It splits the string
"a!===b=!=c"
using the separators slice[]string{"==", "!=", "="}
. - The resulting slice of strings is printed using
fmt.Printf
.
- It splits the string
- Functionality: This is the entry point of the program. It calls the
-
Program Output: The program prints the resulting slice of strings:
["a", "b", "c"]
. This shows that the input string has been split into three parts at the occurrences of the specified separators.
Source code in the go programming language
package main
import (
"fmt"
"strings"
)
func ms(txt string, sep []string) (ans []string) {
for txt > "" {
sepMatch := ""
posMatch := len(txt)
for _, s := range sep {
if p := strings.Index(txt, s); p >= 0 && p < posMatch {
sepMatch = s
posMatch = p
}
}
ans = append(ans, txt[:posMatch])
txt = txt[posMatch+len(sepMatch):]
}
return
}
func main() {
fmt.Printf("%q\n", ms("a!===b=!=c", []string{"==", "!=", "="}))
}
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