How to resolve the algorithm Read a file line by line step by step in the Java programming language
How to resolve the algorithm Read a file line by line step by step in the Java programming language
Table of Contents
Problem Statement
Read a file one line at a time, as opposed to reading the entire file at once.
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Read a file line by line step by step in the Java programming language
Original Code:
This code reads a file line by line, processing each line. It uses a BufferedReader
and FileReader
to read the file in a memory-efficient way. The processLine
method should be implemented to perform some operation on each line.
Exception Handling and File Closing:
The original code uses a finally
block to ensure that the file is closed even if an exception occurs. However, in Java, it is recommended to use the try-with-resources
statement, which automatically closes resources like streams and readers.
Refactored Code:
import java.io.BufferedReader;
import java.io.FileReader;
public class ReadFileByLines {
public static void main(String[] args) {
for (String filename : args) {
try (BufferedReader br = new BufferedReader(new FileReader(filename))) {
String line;
int lineNo = 0;
while ((line = br.readLine()) != null) {
processLine(++lineNo, line);
}
} catch (Exception x) {
x.printStackTrace();
}
}
}
}
Refactored Code Using Java 7:
In Java 7, the try-with-resources
statement can be simplified using automatic resource management (ARM):
import java.nio.file.Files;
import java.nio.file.Paths;
import java.nio.charset.Charset;
import java.io.IOException;
public class ReadFileByLines {
public static void main(String[] args) {
for (String filename : args) {
try {
List<String> lines = Files.readAllLines(Paths.get(filename), Charset.defaultCharset());
int lineNo = 0;
for (String line : lines) {
processLine(++lineNo, line);
}
} catch (IOException | SecurityException e) {
// Problem with the file
}
}
}
}
This code uses the Files.readAllLines
method to read the entire file into a list of strings. It then iterates over the list and processes each line. Exception handling is also simplified using multi-catch.
Source code in the java programming language
import java.io.BufferedReader;
import java.io.FileReader;
/**
* Reads a file line by line, processing each line.
*
* @author $Author$
* @version $Revision$
*/
public class ReadFileByLines {
private static void processLine(int lineNo, String line) {
// ...
}
public static void main(String[] args) {
for (String filename : args) {
BufferedReader br = null;
FileReader fr = null;
try {
fr = new FileReader(filename);
br = new BufferedReader(fr);
String line;
int lineNo = 0;
while ((line = br.readLine()) != null) {
processLine(++lineNo, line);
}
}
catch (Exception x) {
x.printStackTrace();
}
finally {
if (fr != null) {
try {br.close();} catch (Exception ignoreMe) {}
try {fr.close();} catch (Exception ignoreMe) {}
}
}
}
}
}
for (String filename : args) {
try (FileReader fr = new FileReader(filename);BufferedReader br = new BufferedReader(fr)){
String line;
int lineNo = 0;
while ((line = br.readLine()) != null) {
processLine(++lineNo, line);
}
}
catch (Exception x) {
x.printStackTrace();
}
}
import java.nio.file.Files;
import java.nio.file.Paths;
import java.nio.charset.Charset;
import java.io.IOException;
//...other class code
List<String> lines = null;
try{
lines = Files.readAllLines(Paths.get(filename), Charset.defaultCharset());
}catch(IOException | SecurityException e){
//problem with the file
}
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