How to resolve the algorithm Sorting algorithms/Cocktail sort step by step in the C# programming language
How to resolve the algorithm Sorting algorithms/Cocktail sort step by step in the C# programming language
Table of Contents
Problem Statement
The cocktail shaker sort is an improvement on the Bubble Sort. The improvement is basically that values "bubble" both directions through the array, because on each iteration the cocktail shaker sort bubble sorts once forwards and once backwards. Pseudocode for the algorithm (from wikipedia):
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Sorting algorithms/Cocktail sort step by step in the C# programming language
The provided code is an implementation of the Cocktail sort algorithm in C#. Here's how the algorithm works:
-
Initialization:
- The
cocktailSort
method takes an integer arrayA
as input. - It initializes a boolean variable
swapped
tofalse
, which indicates whether any swaps have occurred during the current pass.
- The
-
Sorting Loop:
- The algorithm enters a
do-while
loop that continues as long asswapped
istrue
. This means that at least one swap has occurred during the previous pass, so the algorithm continues sorting.
- The algorithm enters a
-
Forward Pass:
- In the forward pass, the algorithm iterates through the array
A
from the beginning (index 0) to the second-to-last element (indexA.Length - 2
). - For each pair of adjacent elements
A[i]
andA[i + 1]
, it checks ifA[i]
is greater thanA[i + 1]
. If they are in the wrong order, it swaps them using a temporary variabletemp
. - If any swaps occur during this pass,
swapped
is set totrue
.
- In the forward pass, the algorithm iterates through the array
-
Reverse Pass:
- If
swapped
is stilltrue
after the forward pass, it means that the array is not yet sorted. - In the reverse pass, the algorithm iterates through the array
A
from the second-to-last element (indexA.Length - 2
) to the beginning (index 0). - For each pair of adjacent elements
A[i]
andA[i + 1]
, it checks ifA[i]
is greater thanA[i + 1]
. If they are in the wrong order, it swaps them usingtemp
. - If any swaps occur during this pass,
swapped
is set totrue
.
- If
-
Exit Loop:
- The loop continues alternating between forward and reverse passes until no swaps occur in both passes. When
swapped
remainsfalse
after both passes, it means that the array is fully sorted. - The loop then exits, and the sorted array is stored in
A
.
- The loop continues alternating between forward and reverse passes until no swaps occur in both passes. When
Cocktail sort is a simple and stable sorting algorithm that performs multiple passes through the array, swapping adjacent elements that are out of order. It is not as efficient as some more advanced sorting algorithms, but it is easy to implement and understand.
Source code in the csharp programming language
public static void cocktailSort(int[] A)
{
bool swapped;
do
{
swapped = false;
for (int i = 0; i <= A.Length - 2; i++)
{
if (A[i] > A[i + 1])
{
//test whether the two elements are in the wrong order
int temp = A[i];
A[i] = A[i + 1];
A[i + 1] = temp;
swapped = true;
}
}
if (!swapped)
{
//we can exit the outer loop here if no swaps occurred.
break;
}
swapped = false;
for (int i = A.Length - 2; i >= 0; i--)
{
if (A[i] > A[i + 1])
{
int temp = A[i];
A[i] = A[i + 1];
A[i + 1] = temp;
swapped = true;
}
}
//if no elements have been swapped, then the list is sorted
} while (swapped);
}
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