How to resolve the algorithm 99 bottles of beer step by step in the Processing programming language
Published on 12 May 2024 09:40 PM
How to resolve the algorithm 99 bottles of beer step by step in the Processing programming language
Table of Contents
Problem Statement
Display the complete lyrics for the song: 99 Bottles of Beer on the Wall.
The lyrics follow this form: ... and so on, until reaching 0 (zero). Grammatical support for 1 bottle of beer is optional. As with any puzzle, try to do it in as creative/concise/comical a way as possible (simple, obvious solutions allowed, too).
Let's start with the solution:
Step by Step solution about How to resolve the algorithm 99 bottles of beer step by step in the Processing programming language
Source code in the processing programming language
for (int i = 99; i > 0; i--) {
print(i + " bottles of beer on the wall\n"
+ i + " bottles of beer\nTake one down, pass it around\n"
+ (i - 1) + " bottles of beer on the wall\n\n");
}
int i = 99;
void setup() {
size(200, 140);
}
void draw() {
background(0);
text(i + " bottles of beer on the wall\n"
+ i + " bottles of beer\nTake one down, pass it around\n"
+ (i-1) + " bottles of beer on the wall\n\n",
10, 20);
if (frameCount%240==239) next(); // auto-advance every 4 secs
}
void mouseReleased() {
next(); // manual advance
}
void next() {
i = max(i-1, 1); // stop decreasing at 1-0 bottles
}
i = 99
def setup():
size(200, 140)
def draw():
background(0)
text("{} bottles of beer on the wall\n".format(i) +
"{} bottles of beer\n".format(i) +
"Take one down, pass it around\n" +
"{} bottles of beer on the wall\n\n".format(i - 1),
10, 20)
if frameCount % 240 == 239: # auto-advance every 4 secs
next()
def mouseReleased():
next() # manual advance
def next():
global i
i = max(i - 1, 1) # stop decreasing at 1-0 bottles
setup <- function() {
stdout$print(bottlesong(99))
}
bottlesong <- function(num) {
verses = ""
for(i in num:1){
verses = paste0(verses,
num," bottles of beer on the wall \n",
num," bottles of beer \n",
"Take one down, pass it around \n",
num-1, " bottles of beer on the wall \n\n", sep="");
num <- num - 1
}
return(verses)
}
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