How to resolve the algorithm Anagrams step by step in the Ruby programming language
How to resolve the algorithm Anagrams step by step in the Ruby programming language
Table of Contents
Problem Statement
When two or more words are composed of the same characters, but in a different order, they are called anagrams. Using the word list at http://wiki.puzzlers.org/pub/wordlists/unixdict.txt, find the sets of words that share the same characters that contain the most words in them.
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Anagrams step by step in the Ruby programming language
Source Code Explanation:
Version 1
-
Hash Initialization:
anagram = Hash.new {|hash, key| hash[key] = []}
This initializes a Hash that creates an empty array for each unique key. It will be used to group words by their sorted characters, creating anagram groups.
-
Reading the Word List:
URI.open('http://wiki.puzzlers.org/pub/wordlists/unixdict.txt') do |f| words = f.read.split end
This opens a URI and reads the contents of the Unix dictionary file into an array of words.
-
Creating Anagram Groups:
for word in words anagram[word.split('').sort] << word end
For each word, it sorts the characters and adds the word to the corresponding array in the
anagram
Hash. This effectively groups anagrams together. -
Finding the Maximum Group Size:
count = anagram.values.map {|ana| ana.length}.max
This finds the maximum number of anagrams in any group.
-
Printing Anagram Groups with the Maximum Size:
anagram.each_value do |ana| if ana.length >= count p ana end end
This iterates over the anagram groups and prints any group with a size greater than or equal to the maximum size found in the previous step.
Version 2
This version utilizes Ruby's powerful grouping features and lambda syntax.
-
Loading the Word List:
anagrams = open('http://wiki.puzzlers.org/pub/wordlists/unixdict.txt'){|f| f.read.split.group_by{|w| w.each_char.sort} }
It loads the word list and groups the words by their sorted characters using the
group_by
method, creating a Hash of anagram groups. -
Finding the Largest Group Size:
anagrams.values.group_by(&:size).max.last
This finds the group with the maximum group size by grouping the groups by their size and finding the largest group.
-
Printing Anagram Groups with the Maximum Size:
anagrams.values.group_by(&:size).max.last.each{|group| puts group.join(", ") }
This iterates over the largest anagram groups and prints each group as a comma-separated string.
Main Differences:
- Version 1 uses a manual loop to create and populate the anagram groups, while Version 2 leverages Ruby's built-in grouping capabilities.
- Version 1 explicitly finds the maximum group size, while Version 2 uses a combination of grouping and max functions to find the largest group.
Source code in the ruby programming language
require 'open-uri'
anagram = Hash.new {|hash, key| hash[key] = []} # map sorted chars to anagrams
URI.open('http://wiki.puzzlers.org/pub/wordlists/unixdict.txt') do |f|
words = f.read.split
for word in words
anagram[word.split('').sort] << word
end
end
count = anagram.values.map {|ana| ana.length}.max
anagram.each_value do |ana|
if ana.length >= count
p ana
end
end
require 'open-uri'
anagrams = open('http://wiki.puzzlers.org/pub/wordlists/unixdict.txt'){|f| f.read.split.group_by{|w| w.each_char.sort} }
anagrams.values.group_by(&:size).max.last.each{|group| puts group.join(", ") }
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