How to resolve the algorithm Stair-climbing puzzle step by step in the Arturo programming language

Published on 12 May 2024 09:40 PM

How to resolve the algorithm Stair-climbing puzzle step by step in the Arturo programming language

Table of Contents

Problem Statement

From Chung-Chieh Shan (LtU): Your stair-climbing robot has a very simple low-level API: the "step" function takes no argument and attempts to climb one step as a side effect. Unfortunately, sometimes the attempt fails and the robot clumsily falls one step instead. The "step" function detects what happens and returns a boolean flag: true on success, false on failure. Write a function "step_up" that climbs one step up [from the initial position] (by repeating "step" attempts if necessary). Assume that the robot is not already at the top of the stairs, and neither does it ever reach the bottom of the stairs. How small can you make "step_up"? Can you avoid using variables (even immutable ones) and numbers? Here's a pseudo-code of a simple recursive solution without using variables: Inductive proof that step_up() steps up one step, if it terminates:

The second (tail) recursion above can be turned into an iteration, as follows:

Let's start with the solution:

Step by Step solution about How to resolve the algorithm Stair-climbing puzzle step by step in the Arturo programming language

Source code in the arturo programming language

Position: 0

stepUp: function [].export:[Position][
    startPos: Position
    until -> step [
        Position = startPos + 1
    ]
]

step: function [].export:[Position][
    (0.5 > random 0 1.0)? [
        Position: Position - 1
        print ~"fall (|Position|)"
        false
    ][
        Position: Position + 1
        print ~"rise (|Position|)"
        true
    ]
]

stepUp


  

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